Knowledge in Medical Chemistry
chemistry and petroleum
THIS PDF CONTAINS MCQ AND QUESTION BASED ON PETROLEUM CHEMISTRY
priya mheta
CHEMISTRY
This pdf contains simple mcq with answer based on chemistry(petroleum)
Electronics And Medicine: Applications Of Nanotechnology
Major Contributors:- 1959 - Richard Feynman 1981 - Gerd Binnig and Heinrich Rohrer 1991 - Sumio Liggima Applications in tronics:- Quantum Dots Transitions Energy Production Flexible Electronics Applications in medicine;- Nanorobots Drug Delivery Cancer Therapy Tissue Engineering
VEDANT MILIND ATHAVALE
FLAME PHOTOMETRY
Flame photometry is the measurement of the emission of radiation by neutral atoms, which tells us about the concentration of that particular element in a given sample. The earliest reference was in 1556 when Georgius Agricola mentioned "colors of fumes" produced by ore samples. In the 19th century new improvements and developments became significant. In 1873, Champion, Pellet, and Grenier invented the flame photometer.
BEER LAMBERTS LAW
1 1. A solution of Tryptophan has an absorbance at 280 nm of 0.54 in a 0.5 cm length cuvette. Given the absorbance coefficient of trp is 6.4 × 103 LMol-1cm-1 What is the concentration of a solution? Solution: As A = ε l c l= 0.5 cm A= 0.54 ε = 6.4 × 103 LMol-1cm-1 C=? So c = A/ε l = 0.54 / 6.4 × 103 × 0.5 Answer = 0.000168 M 2. Calculate the molar absorptivity of a 1 x 10-4 M solution, which has an absorbance of 0.20, when the path length is 2.5 cm. Solution: A = ε l c l= 2.5 cm A= 0.20 C= 1 x 10 – 4 M ε =? So ε = A / l c = 0.20/ 2.5 ×1 x 10-4 Answer = 800 dm3 /mol/cm. 2 3. The molar absorptivity of a 0.5 x 10-3 M solution is 261.53 dm3 /mol/cm, If it has an absorbance of 0.17, Calculate the path length. Solution: A = ε l c ε = 261.53 dm3 /mol/cm A= 0.17 C= 0.5 x 10-3 M l = ? So l = A / ε c = 0.17/ (261.53 × 0.5 x 10-3) Answer = 1.3 cm. 4. A 1.00 × 10–4 M solution of an analyte is placed in a sample cell with a path length of 1.00 cm. When measured at a wavelength of 350 nm, the solution’s absorbance is 0.139. What is the analyte’s molar absorptivity at this wavelength? l = 1.00 cm c = 1.00 × 10–4 M A=0.139 ε =? So A = ε l c ε = A / l c = 0.139/ 1.0 × 1.00 x 10-4 Answer = 1390 cm−1 M−1
B.Pharma (Carbonyl 5)
the fifth unit: meaning, types, and addition of the reaction and what it forms and the structure.
Sanskruti Dabde
B.Pharma (Carbonyl 6)
the sixth unit: meaning, types, how it becomes semicarbazide, and its reaction with water.
NEET Contact
This pdf contains conatct details about Nantional Testing Agency
Sumit Patil
medical status ESE
medical requirements
class 10 th chemical reaction
this pdf is consist all the important chemicl reaction wiyh example so please you can download. Alloying, or combining different metals, often produces a chemical reaction. This reaction can cause a change in the properties of the metals, such as increased strength or corrosion resistance. The reaction can also produce a new alloy. For example, when aluminum is alloyed with copper, the reaction forms a new alloy called aluminized copper.
Rohit Lodhi